試題1

以太網(wǎng)中的幀屬于 （ ） 協(xié)議數(shù)據(jù)單元。
A、物理層
B、數(shù)據(jù)鏈路層
C、網(wǎng)絡層
D、應用層

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試題2

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試題3

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試題4

依據(jù)我國著作權法的規(guī)定，  （ ）  屬于著作人身權。
A、發(fā)行權
B、復制權
C、署名權
D、信息網(wǎng)絡傳播權

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試題5

在Kerberor認證系統(tǒng)中，用戶首先向  (1)  申請初始票據(jù)，然后從  (2)  獲得會話密鑰。
（1）A、域名服務器DNS
B、認證服務器AS
C、票據(jù)授予服務器TGS
D、認證中心CA
（2）A、域名服務器DNS
B、認證服務器AS
C、票據(jù)授予服務器TGS
D、認證中心CA

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試題6

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試題7

The TCP protocolis a (1) layer protocol. Each connection connects two TCPs that may be just one physical network apart or located on opposite sides ofthe globe. In other words, each connection creates a (2) witha length that may be totally different from another path created by another connection. This means that TCP cannot use the same retransmission time for all connections. Selecting afixed retransnussion time for all connections can result in serious consequences. Ifthe retransmission time does not allow enough time for a (3) to reach the destination and an acknowledgment to reach the source, it can result in retransmission of segments that are still on the way. Conversely, if the retransnussion time is longer than necessary for a short path, it may result in delay for the application programs.Even for one single connection, the retransmission time should not be fixed.A connection may be able to send segments and receive (4)faster during nontraffic period than during congested periods. TCP uses the dynamic retransmission time,a transmission time is different for each connection and which may be changed during the same connection. Retransmission time can be made(5)  by basing it on the round-trip time (RTT). Several formulas are used for this purpose.
（1）A、physical
B、network
C、transport
D、application
（2）A、path
B、window
C、response
D、process
（3）A、process
B、segment
C、program
D、user
（4）A、connections
B、requests
C、acknowledgments
D、datagrams
（5）A、long
B、short
C、fixed
D、dynamic

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試題8

下面病毒中，屬于蠕蟲病毒的是  (   。
A、Wom.Sasser病毒
B、Trojan.QQPSW病毒
C、Backdoor.IRCBot病毒
D、Macro.Melissa病毒

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試題9

我國著作權法中， （ ） 系指同一概念。
A、出版權與版權
B、著作權與版權
C、作者權與專有權
D、發(fā)行權與版權

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試題10

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